4 字
1 分钟
Codeforces Round (2022-08-04)
A
#include <bits/stdc++.h>using namespace std;
#define mp make_pair#define pb push_back#define fi first#define se second
typedef long long ll;typedef pair<int, int> pii;
const int maxn = 1e5 + 17;const int N = 1e5;const int mo = 1e9 + 7;
void debug(int x) { printf("??? %d\n", x);}
void debug(int *X, int x) { printf("??? "); for(int i = 1; i <= x; i++) printf("%d%c", X[i], " \n"[i == x]);}
void solve() { int n, ans; scanf("%d", &n); if(n % 3 == 0) ans = n / 3; else if(n % 3 == 2) ans = n / 3 + 1; else if(n >= 4) ans = n / 3 + 1; else ans = 2; printf("%d\n", ans);}
int main() { int T; // T = 1; scanf("%d", &T); // cin >> T; while(T--) { solve(); } return 0;}B
#include <bits/stdc++.h>using namespace std;
#define mp make_pair#define pb push_back#define fi first#define se second
typedef long long ll;typedef pair<int, int> pii;
const int maxn = 1e5 + 17;const int N = 1e5;const int mo = 1e9 + 7;
void debug(int x) { printf("??? %d\n", x);}
void debug(int *X, int x) { // printf("??? "); for(int i = 1; i <= x; i++) printf("%d%c", X[i], " \n"[i == x]);}
int a[maxn];
void solve() { int n, ans; scanf("%d", &n); for(int i = 1; i <= n; i++) a[i] = i; printf("%d\n", n); for(int i = 1; i <= n; i++) { debug(a, n); swap(a[i + 1], a[1]); }
// printf("%d\n", ans);}
int main() { int T; // T = 1; scanf("%d", &T); // cin >> T; while(T--) { solve(); } return 0;}C
#include <bits/stdc++.h>using namespace std;
#define mp make_pair#define pb push_back#define fi first#define se second
typedef long long ll;typedef pair<int, int> pii;
const int maxn = 4e5 + 17;const ll oo = 1e18;
void debug(int x) { printf("??? %d\n", x);}
void debug(int *X, int x) { printf("??? "); for(int i = 1; i <= x; i++) printf("%d%c", X[i], " \n"[i == x]);}
int m, n, a[maxn], b[maxn];
struct SegmentTree { struct node { ll w, lz; } t[maxn * 4]; #define ls (x << 1) #define rs (x << 1 | 1) #define mid ((l + r) >> 1) void push_down(int x) { t[ls].w += t[x].lz; t[ls].lz += t[x].lz; t[rs].w += t[x].lz; t[rs].lz += t[x].lz; t[x].lz = 0; } void push_up(node& nx, node& nl, node& nr) { nx.w = max(nl.w, nr.w); } void build(int x = 1, int l = 1, int r = n) { t[x].lz = 0; if(l == r) { t[x].lz = 0; t[x].w = a[l] + 1 - (l - 1); if(l == 1) t[x].w = 0; // cout << "!!!" << t[x].w << endl; return; } build(ls, l, mid); build(rs, mid + 1, r); push_up(t[x], t[ls], t[rs]); // printf("%d %d %d %lld %lld %lld %lld\n", x, l, r, t[x].mx, t[x].mn, t[x].p, t[x].pp); } void modify(int ml, int mr, ll k, int x = 1, int l = 1, int r = n) { if(ml <= l && r <= mr) { t[x].w += k; t[x].lz += k; return; } push_down(x); if(ml <= mid) modify(ml, mr, k, ls, l, mid); if(mr > mid) modify(ml, mr, k, rs, mid + 1, r); push_up(t[x], t[ls], t[rs]); } node query(int ql, int qr, int x = 1, int l = 1, int r = n) { if(ql <= l && r <= qr) return t[x]; push_down(x); node res, rl, rr; if(ql <= mid) rl = query(ql, qr, ls, l, mid); if(qr > mid) rr = query(ql, qr, rs, mid + 1, r); if(qr <= mid) return rl; if(ql > mid) return rr; push_up(res, rl, rr); return res; }} sgt;
void solve() { scanf("%d", &m); ll ans1 = oo, ans = oo; n = m * 2; for(int i = 1; i <= m; i++) scanf("%d", &a[i]); for(int i = 1; i <= m; i++) scanf("%d", &a[m - i + 1 + m]); // debug(a, n); sgt.build(); for(int i = 1; i <= m + 1; i += 2) { ll tmp = sgt.query(1, n).w; // printf("??? %lld\n", tmp); // printf("??? "); // for(int i = 1; i <= n; i++) printf("%d%c", sgt.query(i, i).w, " \n"[i == n]); ans1 = min(ans1, max(0ll, tmp)); if(i == m + 1) break; sgt.modify(i + 1, 2 * m - i - 1, -2); sgt.modify(2 * m - i, 2 * m - i, (2 * (m - i - 1))); sgt.modify(2 * m - i + 1, 2 * m - i + 1, (2 * (m - i))); } ans = min(ans1 + n - 1, ans); // printf("%lld\n", ans); for(int i = 1; i <= n; i++) b[i] = a[i]; m--; int inv = max(b[n] + 2, b[n - 1] + 1); for(int i = 1; i <= m; i++) a[i] = b[n - i] - inv; for(int i = 1; i <= m; i++) a[i + m] = b[n / 2 - i + 1] - inv; // a[1]++; n -= 2; // a[1] = 0; ans1 = oo; sgt.build(); for(int i = 1; i <= m + 1; i += 2) { ll tmp = sgt.query(1, n).w; // printf("??? %lld\n", tmp); // printf("??? "); // for(int i = 1; i <= n; i++) printf("%d%c", sgt.query(i, i).w, " \n"[i == n]); ans1 = min(ans1, max(0ll, tmp)); if(i == m + 1) break; sgt.modify(i + 1, 2 * m - i - 1, -2); sgt.modify(2 * m - i, 2 * m - i, (2 * (m - i - 1))); sgt.modify(2 * m - i + 1, 2 * m - i + 1, (2 * (m - i))); } ans1 += n - 1; // cout << ans1 << endl; n += 2; ans = min(ans1 + inv, ans);
printf("%lld\n", ans);}
int main() { int T; // T = 1; scanf("%d", &T); // cin >> T; while(T--) { solve(); } return 0;}D
#include <bits/stdc++.h>using namespace std;
#define mp make_pair#define pb push_back#define fi first#define se second
typedef long long ll;typedef pair<int, int> pii;
const int maxn = 2e5 + 17;const int N = 1e5;const int mo = 998244353;
int add(int x, int y) { return (x + y) % mo;}
void debug(int x) { printf("??? %d\n", x);}
void debug(int *X, int x) { // printf("??? "); for(int i = 1; i <= x; i++) printf("%d%c", X[i], " \n"[i == x]);}
int n, k, f[2][maxn], ans[maxn];
void solve() { scanf("%d%d", &n, &k); f[0][0] = 1;
for(int i = 1, c = 1, lst = 0; i <= n; i++, c ^= 1) { int st = k * i + i * (i - 1) / 2; if(st > n) break; // debug(st); // debug(lst); for(int j = st; j <= n; j++) { int tmp = j - (k + i - 1); // f[c][j] = add(f[c ^ 1][tmp], f[c][tmp]); // cout << tmp << endl; f[c][j] = add(tmp >= lst ? f[c ^ 1][tmp] : 0, tmp >= st ? f[c][tmp] : 0); ans[j] = add(ans[j], f[c][j]); } lst = st; // debug(f[c], n); } // debug(f[c ^ 1], n); debug(ans, n); // printf("%d\n", n);
}
int main() { int T; T = 1; // scanf("%d", &T); // cin >> T; while(T--) { solve(); } return 0;} 分享
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Codeforces Round (2022-08-04)
https://blog.treesonsnow.com/posts/codeforces-round-2022-08-04/ 部分信息可能已经过时
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